利用python写的tomcat部署项目后自动重启

在日常开发或者测试过程中，如果项目有升级的情况，需要手动部署并且重启tomcat，现通过python编写了一个监听文件的变化来自动重启的脚本，前提是需要将下面文件restart.bat放在tomcat的bin目录下，涉及到两个文件：

watch_files.py内容如下：

#! /usr/bin/env python

# -*- coding: utf-8 -*-

# 打包 D:\software\Python\Scripts\pyinstaller.exe -Fw watch_files.py

from __future__ import print_function

import os

from datetime import datetime

import time

from threading import Timer

from watchdog.events import FileSystemEventHandler

from watchdog.observers import Observer

WATCH_PATH = 'D:\\software\\apache-tomcat-7.0.63\\webapps' # 监控目录

TOMCAT_PATH = 'D:\\software\\apache-tomcat-7.0.63\\bin\\restart.bat' #TOMCAT目录

STARTING = False

# 监控文件变更

class FileMonitorHandler(FileSystemEventHandler):

def __init__(self, **kwargs):

super(FileMonitorHandler, self).__init__(**kwargs)

# 监控目录

self._watch_path = WATCH_PATH

# 重写文件改变函数，文件改变都会触发文件夹变化

def on_modified(self, event):

global STARTING

if not event.is_directory: # 文件改变都会触发文件夹变化

file_path = event.src_path

print("项目文件已变更: %s " % file_path)

STARTING = True

# 调度任务

def timedTask():

Timer(5, dowork, ()).start()

# 任务工作

def dowork():

while True:

global STARTING

print('dowork:' + str(datetime.now()))

if STARTING:

print('重新启动项目：' + str(datetime.now()))

os.system('chcp 65001')

os.system(TOMCAT_PATH)

STARTING = False

time.sleep(5)

# 主函数

if __name__ == "__main__":

event_handler = FileMonitorHandler()

observer = Observer()

observer.schedule(event_handler, path=WATCH_PATH, recursive=True) # recursive递归的

print('已启动...')

timedTask()

observer.start()

observer.join()

restart.bat内容如下：

@echo off

chcp 65001

echo %~dp0

set current_dir=%~dp0

echo stopping...

ping /n 1 /w 1000 1.0.0.1>nul

::echo %current_dir%shutdown.bat

cd %current_dir%

call %current_dir%shutdown.bat

echo restarting...

ping /n 1 /w 2000 1.0.0.1>nul

echo %current_dir%startup.bat

cd %current_dir%

call %current_dir%startup.bat

echo open browser...

ping /n 1 /w 2000 1.0.0.1>nul

start chrome.exe http://localhost:8080